Kirchhoff’s Loop Rule Part-2

Q. Find the current in the given circuit

Step 1: Assume the direction of current ☝️

💡 Let’s assume the current is anticlockwise.


Step 2: Find potential changes in a closed loop ✌️

📌 Let us take the loop:

A → B → C → D → A

Applying Kirchhoff’s Voltage Law (KVL):5+2I+3I+I+10+5I=0-5 + 2I + 3I + I + 10 + 5I = 0

Combining like terms:5+11I=05 + 11I = 0

Therefore,I=511I = -\frac{5}{11}

📦 Answer:I=511\boxed{I = -\frac{5}{11}}


Interpretation of the negative sign

The negative sign (-) indicates that the actual direction of current is clockwise, opposite to the direction initially assumed.

🔄 Actual current direction = Clockwise


Verification

🔄 Do the same problem again, but this time assume the current to be clockwise.

🎯 You will obtain:I=511\boxed{I = \frac{5}{11}}

✅ The magnitude of current is 511A\frac{5}{11} \, \text{A} and its direction is clockwise.

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